binary search tree c++ searching operation always giving 0; -

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in bst,the searchbst function searching function returning 0 always. not giving 5 or 8 have programmed error in code because of problem there

#include<iostream> using namespace std;  struct bstnode{ bstnode *lchild; int data; bstnode *rchild;     };  void creatbst(bstnode *&t,int k){     if(t=='\0'){         t=new(bstnode);         t->data=k;         t->lchild='\0';         t->rchild='\0';     }     else if(k<t->data){         creatbst(t->lchild,k);     }     else if(k>t->data){         creatbst(t->rchild,k);     } }  int searchbst(bstnode *t,int k){     if(t=='\0')     return 5;     else{       if(k<t->data)     searchbst(t->lchild,k);       else if(k>t->data)     searchbst(t->rchild,k);       else         return 8;     } }  int main(){     bstnode *t;     t='\0';     creatbst(t,36);     creatbst(t,20);     creatbst(t,75);     creatbst(t,42);     creatbst(t,8);     creatbst(t,31);     creatbst(t,25);     creatbst(t,3);     creatbst(t,80);      cout<<endl<<"searching ";     cout<<searchbst(t,3);     cout<<endl<<"searching ";     cout<<searchbst(t,1);     return 0;  }

your code has undefined behavior: if don't follow conditions leading return 5; or return 8; statements, call searchbst(), ignore result, , fall of function. meant return result of searchbst():

return searchbst(t->rchild, k);

btw, have funny way of writing null pointer constant: although '\0' works, conventional way use 0 or nullptr (the latter c++11 way).


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