a string or function that includes multiple variables (c++) -

i've searched multiple places , watched through entire "thenewboston" c++ guide on youtube, , yet find answer this.

i'm writing program practice c++ skills, i'm still noob think possible don't know how it.

the program i'm trying make 1 records how many reps excercise when training in gym.

#include <iostream> #include <cstdlib> #include <string>  using namespace std;  int main() {     string biceps = "biceps";     string triceps = "triceps";     string quads = "quads";     string musclechoice;      cout << "welcome mypt!" << endl;     cout << endl;     cout <<  "what going training today?" << endl;     cout << endl;     cout << "**biceps** \n\n**triceps** \n\n**quads**" << endl;     cout << endl;     cin >> musclechoice;     if ((musclechoice == "biceps") || (musclechoice == "triceps") || (musclechoice == "quads"))     {         cout << "working" << endl;     }        return 0; } 

that's want, , works. if have more possibilities, messy. want looks this. (obviously function wouldn't long, tried explain better)

cin >> musclechoice;  if (musclechoice == onefunctionthatincludesallthosestrings) {     cout << "working" } 

does know how that?

(please explain answer might not understand, i'm noob)

you use std::set of exercise strings, , check input string member of set:

std::set<std::string> exercises{"biceps", "triceps", "quads"}; 

then

if (exercises.find(musclechoice) != exercises.end()) {   std::cout << "working"; } 

if want keep tally of reps, use std::map instead:

std::map<std::string, unsigned int> exercises;  if (exercises.find(musclechoice) != exercises.end()) {   std::cout << "working";   exercises[musclechoice]++; // increase count muscle choice }