Invalid syntax on ".perform()" with Python -

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i trying download zip file ubuntu 10.04 workstation , limit transmit limit 100 kb/s. when running script following:

  file "./iso.py", line 7     iso.perform()       ^ syntaxerror: invalid syntax

here code using. not sure actual syntax error is. have searched google while before asking here. appreciated.

#!/usr/bin/env python import pycurl iso = pycurl.curl() iso.setopt(iso.url, "http://downloads.sourceforge.net/sevenzip/7za920.zip") iso.setopt(iso.max_recv_speed_large, 100000) iso.setopt(iso.writedata, file("7za920.zip") iso.perform()

fyi running python version 2.6.5

you forgot parenthesis after previous line.

change:

iso.setopt(iso.writedata, file("7za920.zip")

to:

iso.setopt(iso.writedata, file("7za920.zip"))

python interpretting if continuing add function (eg, add more parameters). there's syntaxerror because there's no comma.


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