windows - How do I print the return value of a program in a loop in a batch file script? -

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the task run program(the same program) ten times , output each run exit code(the return value of main function). want run batch file(windows), this:

for /l %%x in (1,1,10) (     automatedtest.exe cip.log     echo %errorlevel% )

the code above should if you're thinking intuitively, doesn't work because code it's running actually:

(     automatedtest.exe cip.log     echo 0 )

and piece executed 10 times.

any ideas on how make work? thanks!

what need delayed variable expansion:

for /l %%x in (1,1,10) (     automatedtest.exe cip.log     echo !errorlevel! )

to enable delayed variable expansion precede batch setlocal enabledelayedexpansion or start command shell cmd.exe /v:on.

another approach using subroutines:

for /l %%x in (1,1,10) call :test goto :eof  :test automatedtest.exe cip.log echo %errorlevel% goto :eof

yet approach use if errorlevel.


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