Odd string split in ruby? -

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i have expression "1=2,3=(4=5,6=7)" , want create hash out of - 1 => 2, 3 => (4=5,6=7). can in 2 passes. in first pass, can transform (.*) (4;5,6;7) , in 2nd pass split.

any better solutions?

as long don't need worry nested parentheses, , inside parentheses treated plain string:

str = "1=2,3=(4=5,6=7)"  hash[str.scan(/([^=,]+)=(\([^\)]+\)|[^=,]+)/)] # => {"1"=>"2", "3"=>"(4=5,6=7)"}

if need nested hashes, use recursive method:

def hashify(str)   arr = str.scan(/([^=,]+)=(\([^\)]+\)|[^=,]+)/).map |key, val|     if val[0] == '(' && val[-1] == ')'       [key, hashify(val[1..-2])]     else       [key, val]     end   end   hash[arr] end  hashify "1=2,3=(4=5,6=7)" # => {"1"=>"2", "3"=>{"4"=>"5", "6"=>"7"}}

note still doesn't handle nested parentheses properly. need proper parser that.


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