int vs Integer comparison Java -

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this question has answer here:

class datatype1 {      public static void main(string args[])     {     int i1 = 1;     integer i2 = 1;     integer i3 = new integer(1);      system.out.println("i1 == i2"+(i1==i2));     system.out.println("i1 == i3"+(i1==i3));     system.out.println("i2 == i3"+(i2==i3)); }  }

output

i1 == i2true i1 == i3true i2 == i3false

can explain why false when comparing i2 , i3 ?

i1 == i2

results in un-boxing , regular int comparison done. (see first point in jls 5.6.2)

i2 == i3

results in reference comparsion. remember, i2 , i3 2 different objects. (see jls 15.21.3)


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