Python regex: find and replace commas between quotation marks -

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i have string,

line = '12/08/2013,3,"9,25",42:51,"3,08","12,9","13,9",159,170,"3,19",437,'

and find , replace commas, between quotation marks, ":". looking results 

line = '12/08/2013,3,9:25,42:51,3:08,12:9,13:9,159,170,3:19,437,'

so far have been able match pattern with,

import re re.findall('(\"\d),(.+?\")', line)

however, guess should using 

re.compile(...something..., line) re.sub(':', line)

does know how this? thanks, labjunky

>>> import re >>> line = '12/08/2013,3,"9,25",42:51,"3,08","12,9","13,9",159,170,"3,19",437,' >>> re.sub(r'"(\d+),(\d+)"', r'\1:\2', line) '12/08/2013,3,9:25,42:51,3:08,12:9,13:9,159,170,3:19,437,'

\1, \2 refer matched groups.

non-regex solution:

>>> ''.join(x if % 2 == 0 else x.replace(',', ':')             i, x in enumerate(line.split('"'))) '12/08/2013,3,9:25,42:51,3:08,12:9,13:9,159,170,3:19,437,'

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