bytearray - how to convert bit array into hex contanning 8bits in java -

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i have binary array converted hex using

    stringbuilder sb = new stringbuilder();     (byte b : bytes)      {         sb.append(string.format("%02x ", b));     }     system.out.println(sb.tostring());

but gives me hex code respective bit.

i want hex containing 8bits. please me.

you want this-

biginteger bint = new biginteger(1, bytes); string hexstring = string.format("%0" + (bytes.length << 1) + "x", bint);

for lower case hex digits, can use-

string hexstring = string.format("%0" + (bytes.length << 1) + "x", bint);

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